A well is dug 14m deep . Its radius is 2 m. The earth dug out is evenly spread out on the rectangular field of dimensions 10 m * 4 m. Find the height of the platform rest
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well!!! height of well =14m and radius=2m
so, volume of dug out earth= πr^2h
=π2×2×14
=22×4×14/7
=176m^3
as we know that volume of dig out earth=volume of reactangular field
so, l×b×h=176m^2
or 10×4×h=176m^2
or h=176/40
.•. height=4.4m answer
so, volume of dug out earth= πr^2h
=π2×2×14
=22×4×14/7
=176m^3
as we know that volume of dig out earth=volume of reactangular field
so, l×b×h=176m^2
or 10×4×h=176m^2
or h=176/40
.•. height=4.4m answer
kamya7:
wrong answer
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