Question

a well is dug 14m deep .its radius is 2m .the earth dug out is evenly spread out on a rectangular field of dimensions 10×4m.find height of the platform raised​

Answer 1

HEY MATE,ACC. TO YOUR QUESTION,

well!!! height of well =14m and radius=2m

so, volume of dug out earth= πr^2h

=π2×2×14

=22×4×14/7

=176m^3

as we know that volume of dig out earth=volume of reactangular field

so, l×b×h=176m^2

or 10×4×h=176m^2

or h=176/40

.•. height=4.4m answer