a well is dug 14m deep. its radius is 2m. the earth dug out is evenly spread out on a rectangular field of dimensions 10m*4m. Find the height of the platform raised.
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Volume of Earth dug= πr^2h
= 22/7 × 2×2×14
= 126 cm
Area of field= length×breadth
= 10×4
= 40cm sq
Height raised= volume/ area
= 126/40
= 3.15 m
I guess this is right.
= 22/7 × 2×2×14
= 126 cm
Area of field= length×breadth
= 10×4
= 40cm sq
Height raised= volume/ area
= 126/40
= 3.15 m
I guess this is right.
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