a well is dug 20 m Deep and it has the diameter of 7m. the Earth which is so dug out is spread evenly on rectangular plot 22 m long and 14m broad .what is the height of the platform formed
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Given = diameter of well = 7 m
height of well = 20 m
length of platform = 22 m
breadth of platform = 14 m
solution:
In this situation volume of platform (rectangular in shape) = volume of well (cylindrical in shape).
so,
L*B*H = pi*r²h
22*14*H = 22/7*7/2*7/2*20
22*14*H = 11*49*10/7 [as, 2*11=22 and 2*10=20]
H = 11*49*10/7*14*22
H= 5/2
H =2.5 m
height of well = 20 m
length of platform = 22 m
breadth of platform = 14 m
solution:
In this situation volume of platform (rectangular in shape) = volume of well (cylindrical in shape).
so,
L*B*H = pi*r²h
22*14*H = 22/7*7/2*7/2*20
22*14*H = 11*49*10/7 [as, 2*11=22 and 2*10=20]
H = 11*49*10/7*14*22
H= 5/2
H =2.5 m
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