Question

a well is dug 20 metre Deep and it has a diameter 7m the Earth which is so dug out is spread evenly or a rectangular plot 22 M long and 14 M broad what is the height of platform formed

Answer 1

The volume of earth dug out = pir^2h .
22/7 × 20 × 7/2 × 7/2 = 770 m^3 .

vol of earth dug out = vol of plot

770=lbh
770= 22×14×h
5=h
height= 5m

Answer 2

⇒ Given:- Height (h) of well :- 20m

Diameter (d) :- 7 m

Radius (r) :- 7/2 m

Volume of earth platform :- 22 m by 14m

⇒ To find :- Height of the platform:- ?

⇒ Solution:-

Volume of cylinder of radius 7/2 m and height 20 m

Volume of cylinder :- π(r^2)(h)

= 22/7×(7/2^2)×20 m^3

= 770 m^3

Let the height raised by 22 m × 14 m platform be equal to h metres

Therefore,

Volume of the earth in platform = Volume of the earth taken out of the well

22 × 14 × h = 770

h = 770/22 × 14 m

h = 5/2 m

h = 2.5 m

Hence , the height of the platform is 2.5 m.