Question

A well is dug 20 metre deep and its it has a diameter 7m the earth which is so dug out is spread evenly on a rectangular plot 22 m long and 14 m broad what is the height of the platform formed

Answer 1

Hey mate!

Here's your answer!!

Volume of the earth dug out
= 22/7 x 7/2 x 7/2 x 20
= 770

Area of the rectangular field
= 22 x 14
= 308

We know that,

Volume = area x height

So, Height = Volume/Area

= 770/308

= 2.5m

Hope it helps you!

Answer 2

⇒ Given:- Height (h) of well :- 20m

Diameter (d) :- 7 m

Radius (r) :- 7/2 m

Volume of earth platform :- 22 m by 14m

⇒ To find :- Height of the platform:- ?

⇒ Solution:-

Volume of cylinder of radius 7/2 m and height 20 m

Volume of cylinder :- π(r^2)(h)

= 22/7×(7/2^2)×20 m^3

= 770 m^3

Let the height raised by 22 m × 14 m platform be equal to h metres

Therefore,

Volume of the earth in platform = Volume of the earth taken out of the well

22 × 14 × h = 770

h = 770/22 × 14 m

h = 5/2 m

h = 2.5 m

Hence , the height of the platform is 2.5 m.