Question

A well is dug 20m deep and it has a diameter 7 m. The earth which is so dug out is spread evenly on a rectangular plot 22 m long and 14 m broad. What is the height
of platform formed?​

Answer 1

Answer: volume of earth dug out = 22/7 × 3.5 ×3.5 × 20 m³

Height of the platform = volume of earth / area of land

Height of the platform = 22 × 3.5 × 3.5 × 20/22×14×7

= 2.5 m

Mark me as brainliest

Answer 2

Answer:

The height  of platform formed is 2.5 m

Step-by-step explanation:

Well is in cylindrical shape,

Volume of the well dug is equal to the volume of the rectangular field.

Volume of the cylinder =Volume of rectangular field

$\pi r^2h'=lbh$

here r=d/2=7/2=3.5 m

h'=20 m

l= 20m

b= 14m

Substitute all the values in above equation , we get h

$\pi r^2h'=lbh\\\pi \times 3.5^2\times20=22\times14\times h\\h=\frac{769.69}{308} \\h=2.5 m$

The height  of platform formed is 2.5 m