Question

A well is dug 20m deep and it has a diameter 7m the earh which is so dug out is spread evanly on a rectangular plot 22m lOng and 14m broad what is the height of platform formed?

Answer 1

volume oo well=πr^2h =22/7×7×7×29=3080cm^3
3080=22×14×h=308×h
3080/308=h
height =10cm

Answer 2

$\mathbb{SOLUTION}$:

The well is dug 20m deep.
Diameter is 7m.

So, the well is in the form of cylinder.

We know that,
radius = $\frac{diameter}{2}$ = $\frac{7}{2}$ m

According to the question,
The Earth which is dug out is spread evenly on a rectangular plot 22m long and 14m broad.

So,
length of the rectangular plot is 22m and breadth is 14m.

Now,

$\bf{Volume \:of \:the \:cylinder = Volume\: of \:the \:rectangular \:plot }$

=> πr²h = length × breadth × height

$= > \frac{22}{7} \times {( \frac{7}{2} )}^{2} \times 20 = 22 \times 14 \times height$

=> 770 = 308 × height

=> $\frac{770}{308}$ = height

=> 2.5 = height

Hence, the height of the rectangular plot is 2.5m