Question

A well is dug 36 m deep and it has a diameter 14m. The Earth which is
so dug out is spread evenly on a rectangular plot 28 m long and 22m
broad. What is the height of platform formed.​

Answer 1

Step-by-step explanation:

volume of earth is taken out =volume of the well

=πr²h

=22/7×7×7×36

=154×36

=5544m³

since,it is spread on a rectangular plot 28 m long and 22m

let height be =H

volume of the field increase = volume of the well

l×b×h = 5544m³

28m×22m ×h = 5544cm³

616cm²×h = 5544cm³

H = 5544cm³/616cm²

H = 9 cm

hence, the height of platform 9cm formed.