A well is dug 36 m deep and it has a diameter 14m. The Earth which is
so dug out is spread evenly on a rectangular plot 28 m long and 22m
broad. What is the height of platform formed.
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Step-by-step explanation:
volume of earth is taken out =volume of the well
=πr²h
=22/7×7×7×36
=154×36
=5544m³
since,it is spread on a rectangular plot 28 m long and 22m
let height be =H
volume of the field increase = volume of the well
l×b×h = 5544m³
28m×22m ×h = 5544cm³
616cm²×h = 5544cm³
H = 5544cm³/616cm²
H = 9 cm
hence, the height of platform 9cm formed.
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