Question

A well is dug out whose radius is 2.5m and depth is 63m if the earth taken out from well is spread all over a rectangular field whose dimensions are 30m×28m. find the rise in level of the rectangular field

Answer 1

Answer:

1.47 rise of level of rectangular feild

Answer 2

The rise in level of the rectangular field is 1.47 m

Step-by-step explanation:

Radius of well = 2.5 m

Depth of well = 63 m

Volume of well = $\pi r^2 h = \frac{22}{7} (2.5)^2 (63)=1237.5 m^2$

We are given that The earth taken out from well is spread all over a rectangular field whose dimensions are 30m×28m.

Let the the rise in level of the rectangular field be h

So, Volume of well = Volume of rectangular field

$1237.5 = 30 \times 28 \times h$

$\frac{1237.5}{30 \times 28}=h$

1.47 m = h

Hence the rise in level of the rectangular field is 1.47 m

#Learn more:

A well is dug out whose radius is 4.2 m and depth is 38

m. The earth taken out from well is spread all over a

rectangular field whose dimensions are 130 m x 115 m.

Find the rise in the level of field.​

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