Math, asked by shashank98182, 5 months ago

A well is dug with 14 m diameter
and a depth of 10 m. The earth taken out is
spread evenly on a plot of land 100 m long and
7 m wide. Find the height of the platform thus
formed by the earth.​

Answers

Answered by Anonymous
8

Question :-

 

      → A well is dug with 14 m diameter

        and a depth of 10 m. The earth taken out is

        spread evenly on a plot of land 100 m long and

        7 m wide. Find the height of the platform thus

        formed by the earth.​

Given :-

     

  → Inner Diameter of the well= 14 m

  → Inner Radius of the well (r) = 14/2 m = 7 m

   → Height of the well (h) = 15 m

   →   Width =  7m

Solution :-

   → Volume of the earth taken out of the well = πr²h

          \frac{22}{7} \times 7 \times 7 \times 15

        = 22 × 7 × 15= 2310 m³

       

→  Outer radius of the embankment ( R )

        =inner radius + width

→ Outer radius  ( R ) = 7 + 7 = 14m

→ The embankment is in the form of cylindrical shell, so area of embankment

→ Area of embankment = outer area - inner area

       = πR² - πr² = π(R²-r²)

       = (22/7) ( 14² - 7²)

       = 22/7(196-49)

       = 22/7 × 147

       = 22 × 21

       = 462 m²

→ Volume of embankment

= volume of earth taken out on digging the well

→ Area of embankment × height of embankment= volume of earth dug out

→ Height of embankment= volume of earth dug out ÷ area of the embankment

→ Height of the embankment = 2310 ÷ 462

→ Height of embankment = 5 m

 \huge{\orange{\boxed{\boxed {\boxed{\purple{\underline{\underline{\red{\mathfrak{h = 5 m }}}}}}}}}}


VerifiedJaat: nice answer
Similar questions