a well of diameter 10 m is dug 14 m deep. the earth taken out is spread evenly to form a rectangular platform of base 11 m x 10 m .find the height of the platform
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Well with diameter 10 m is dug 14 m deep.
= cylindrical radius =10/2 m = 5m
Volume = πr square h
=22/7 × 5 × 5 × 14
=1100 cubic metres
1100 cubic metres is taken out and spread width of 5 m.
R1 = 5+5 m =10 m
So, r = 5 m
V = π(R square - r square) h
1100 = 22/7 (10 square - 5 square) h
350 = (100 -25 ) h
h = 350/75
h = 14/3
h = 4.66 m.
Hence, the height of platform is 4.66 m
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