Math, asked by shaunnn634, 9 months ago

A well of diameter 2 m is dug 14 m deep. The earth taken out of it is spread evenly all around it to form and embankment of height 40 cm. Find the width of the embankment.

Answers

Answered by ANGEL123401
43

{\huge{\underline{\underline{\rm{\bold{QuestiOn:}}}}}}

━━━━━━━━❪❐❫━━━━━━━━

➽A well of diameter 2 m is dug 14 m deep. The earth taken out of it is spread evenly all around it to form and embankment of height 40 cm. Find the width of the embankment.

━━━━━━━━❪❐❫━━━━━━━━

{\huge{\underline{\underline{\rm{\bold{SolutiOn:}}}}}}

❀Let us suppose the shape of well is like as cylinder.

Diameter of well = 2 m

so, radius (r) = d/2 = 2/2 = 1 m

Height(h) of well = 14 m

❀Volume of right circular cylinder, V’ = πr²h

=π×1²×14.....................(1)

Given that,

length(l) of embankment= 40 cm

Let width of the embankment be x m

❀Volume of the embankment, V’’ = πr²h

= π ((1+x)2 – 1)2 x 0.4 ....................(2)

❀Since well is spread evenly to form the embankment,

so their volumes, V’ = V’’

➽ π × 14 = π ((1+x)2 – 1)2 x 0.4

➽ x = 5m

{\bf{\green{∴ Height\: of \:the\: embankment,\: x = 5cm}}}

━━━━━━━━━━━━━━━━━━━━━━━━━

━━━━━━━━━━━━━━━━━━━━━━━━━

Answered by topwriters
0

Width of embankment = 5m

Step-by-step explanation:

Volume of the well = πr²h = 22/7 * 1 * 1 * 14 = 44 cu. m.

Radius of the quadrant = 3.5 m.

Let x be the width of the embankment.

Height of the embankment = 40cm = 0.4 m

Volume of the embankment = πr²h =  π ((1+x²) -1)² * 0.4

Both volumes are equal, so we get:

 π(1)(14) = π ((1+x²) -1)² * 0.4

 14/0.4 = (1+x²)² +1 -2(1+x)

   x = 5m

Width of embankment = 5m

Similar questions