Math, asked by BrainlyHelper, 1 year ago

A well of diameter 2 m is dug 14 m deep. The earth taken out of it is spread evenly all around it to form an embankment of height 40 cm. Find the width of the embankment.

Answers

Answered by nikitasingh79
12

Answer:

Width of the embankment is  5 cm.

Step-by-step explanation:

Given :  

The height of the deep well is in the form of a cylinder, H = 14 m

Diameter of well = 2 m

radius of well , r = 1 m

Volume of cylinder = πr²hH

= π × 1² × 14  = 14π m³

Volume of cylinder = 14π m³ ………(1)

The Embankment is in the form of cylindrical shell.  

Height of embankment , h = 4 cm = 40/100 = 0.4 m

Let the width of the embankment be x

width of the embankment = R - r  

Outer Radius of the embankment , R = (r + x) = (1 + x )

Inner  Radius of the embankment , r = 1

Volume of embankment = π(R² - r²)h

= π( (1+ x)² - 1²)× 0.4

Volume of embankment = π (1² + x² + 2x - 1) 0.4 ……….(2)

Here, the earth obtained from digging the well of cylindrical shape is used to make a Embankment. So the volume of Earth will be equal to the volume of cylindrical well and it will be equal to volume of Embankment

Volume of the deep well (cylinder)  = Volume of Embankment

14π = π (1² + x² + 2x - 1 ) 0.4

[From eq 1 & 2]

14/.4 = 1 + x² + 2x - 1

140/4 = x² + 2x  

35 = x² + 2x  

x² + 2x - 35 = 0

x² + 7x - 5x - 35 = 0

[By middle term splitting]

x(x + 7) - 5(x + 7) = 0

(x - 5) (x + 7) = 0

(x - 5) = 0  or  (x + 7) = 0

x = 5  or x = - 7  

Since, width can't be negative , so x ≠ - 7  

Therefore, x = 5  

Hence, width of the embankment is  5 cm.

HOPE THIS ANSWER WILL HELP YOU….


siddi8808: My answer is easy
Answered by siddi8808
6

Answer:

Solution:-

Diameter of well = 2 m

So, radius of well = 1 m

Height = 14 m

Dimensions of embankment =

h = 40 cm or 0.4 m

Radius = ?

Width of embankment = R - r

Volume of earth dug out = Volume of embankment

⇒ 22/7*1*1*14 = 22/7*(R² - 1)*0.4

⇒ 44 = 8.8(R² - 1)/7

⇒ = R² - 1 = (44*7)/8.8

⇒ R² - 1 = 35

⇒ R² = 35 + 1

⇒ R² = 36

⇒ R = 6 m

Now width of embankment = 6 - 1

= 5 m

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