A well of diameter 2m is dug 14m deep.The earth taken out of it is spread evenly around to a width of 5m to form an embankment. Find the height of the embankment.
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2
Let us assume shape of well is like a solid circular cylinder
Radius of cylinder, r = 2/2 = 1m
Depth(height) of well, h = 14m
Volume of right circular cylinder, V’ = π r2 h
---------(I)
Given that, length of embankment, l = 40 cm
Let width of the embankment be x m
Volume of the embankment, V’’ = π r2 h
= π ((1+x)2 – 1)2 x 0.4 -----------(II)
Since well is spread evenly to form the embankment, so their volumes, V’ = V’’
⇒ π × 14 = π ((1+x)2 – 1)2 x 0.4
⇒ x = 5m
∴ Height of the embankment, x = 5cm
Radius of cylinder, r = 2/2 = 1m
Depth(height) of well, h = 14m
Volume of right circular cylinder, V’ = π r2 h
---------(I)
Given that, length of embankment, l = 40 cm
Let width of the embankment be x m
Volume of the embankment, V’’ = π r2 h
= π ((1+x)2 – 1)2 x 0.4 -----------(II)
Since well is spread evenly to form the embankment, so their volumes, V’ = V’’
⇒ π × 14 = π ((1+x)2 – 1)2 x 0.4
⇒ x = 5m
∴ Height of the embankment, x = 5cm
Answered by
1
d=2
r=1
height=14
Vol of well= pie ×r^2×h
=22/7×1×1×14
=44 cubic metres
width of embankment=5m
Now to find height
height= volume/22/7 (2^2-1^2)
= 44×7×3/22
=42 m..
hope it helps..
Please mark as brainliest
r=1
height=14
Vol of well= pie ×r^2×h
=22/7×1×1×14
=44 cubic metres
width of embankment=5m
Now to find height
height= volume/22/7 (2^2-1^2)
= 44×7×3/22
=42 m..
hope it helps..
Please mark as brainliest
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