Math, asked by teena140306, 6 months ago

A well of diameter 3 m is dug 14 m deep. The earth taken out of it has been spread evenly
all around it in the shape of a circular ring of width 4 m to form an embankment. Find the
height of the embankment.​

Answers

Answered by Anonymous
0

Answer:

The shape of the well will be cylindrical as shown in the figure below:

Given:

Depth (h

1

) of well = 14 m

Radius (r

1

) of the circular end of well =

2

3

m

Width of embankment = 4 m

From the figure, it can be observed that our embankment will be in a

Answered by Anonymous
0

Answer:

The shape of the well will be cylindrical as shown in the figure below:

Given:

Depth (h

1

) of well = 14 m

Radius (r

1

) of the circular end of well =

2

3

m

Width of embankment = 4 m

From the figure, it can be observed that our embankment will be in a cylindrical shape having outer radius, (r

2

)=4+

2

3

=

2

11

m,

Let height of embankment be h

2

.

Volume of soil dug from well = Volume of earth used to form the embankment

π×r

1

2

×h

1

=π×(r

2

2

−r

1

2

)×h

2

⟹π×(

2

3

)

2

×14=π×[(

2

11

)

2

−(

2

3

)

2

×h

2

]

4

9

×14=

4

112

×h

2

⟹h

2

=

8

9

=1.125 m

So, the height of the embankment will be 1.125 m.


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