Math, asked by sana14386, 11 months ago

A well of diameter 3m is dug 14m deep. the earth taken out of its has been spread evenly all around it in the shape of a circular ring of width 4m to form an embankment Find the height of embankment...............​

Answers

Answered by Anonymous
0

Answer:

1.125 m

Step-by-step explanation:

let the diameter of the well of cylindrical shape is. d= 3m ,

r(cy)= 3/2 = 1.5 m

h(cy)= 14m

The earth taken out spread around it in the form of ring whose width is 4m , then the outer of the ring is r(0) =. (4+1.5)=5.5m

volume of well = volume of embankment

πrsquare h = π(Rsquare - rsquare) h

3/2 (3/2)(14) = (5.5) square - (1.5) square h

63/2 = 28 h

63/2(28) =h

h= 63/56

h= 1.125m

Answered by Anonymous
2

Step-by-step explanation:

Height of the well = 14 m.

Diameter of the well = 3m.

Therefore, Radius of the well = 3/2 m.

According to question now :

Volume of the earth taken out of the well = πr²h

=> 22/7 × 3/2 × 3/2 × 14

=> 22 × (3/2)² × 2

=> 44 × 9/4

=> 11 × 9

=> 99 cm.

Outer radius of embankment (R) = (3/2 +4)

=> 11/2 m

Now,

Area of embankment = outer area - inner area

=> πR² - πr²

=> 22/7 [(11/2)² - (3/2)²]

=> 22/7 × 112/4

=> 88 m²

Height of the embankment = Volume / Area

=> 99/88

=> 1.125 m

Therefore, the height of the embankment is 1.125 m

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