A well of inner diameter 14 m is dug to a depth of 15 m. Earth taken out of it has been evenly spread all around it to a width of 7 m to form an embanknent. Find the height of the embankment so formed.
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Radius=7m.
Height=15m.
Volume of land dug= πr^2h
=22/7*7*7*15
=2310m^3
Area of the land dug up= πr^2
=22/7*7*7
=154m^2
Area of the land over which the dug up soil is to be spread= (πR^2)-(πr^2)
= (22/7*14*14)-(154m^2)
= (616-154) m^2
= 462m^2
Height of embankment= Volume of land dug up/Area over which soil is to be spread
= (2310/462) m.
= 5 m.
Therefore, the height of the embankment so formed will be 5m.
Height=15m.
Volume of land dug= πr^2h
=22/7*7*7*15
=2310m^3
Area of the land dug up= πr^2
=22/7*7*7
=154m^2
Area of the land over which the dug up soil is to be spread= (πR^2)-(πr^2)
= (22/7*14*14)-(154m^2)
= (616-154) m^2
= 462m^2
Height of embankment= Volume of land dug up/Area over which soil is to be spread
= (2310/462) m.
= 5 m.
Therefore, the height of the embankment so formed will be 5m.
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