A well of inner diameter 14m is dug to a depth of 15m,mud taken out of it has been evenly spread all around into a width of 7m to form an embankment .find the height of the embankment so formed.
Answers
Answered by
335
Here, a well is dug and Earth taken out of it is used to form an embankment.
Given:
Inner Diameter of the well= 14 m
Inner Radius of the well (r) = 14/2 m = 7 m
Height of the well(h) = 15 m
Volume of the earth taken out of the well = πr²h
= 22/ 7 ×(7)²×15
= 22× 7×15= 2310 m³
Width= 7m
Outer radius of the embankment R =inner radius + width
Outer radius (R)= 7 + 7 = 14m
The embankment is in the form of cylindrical shell, so area of embankment
Area of embankment = outer area - inner area
= πR² - πr² = π(R²-r²)
= (22/7) ( 14² - 7²)
= 22/7(196-49)
= 22/7 × 147
= 22 × 21
= 462 m²
Volume of embankment= volume of earth taken out on digging the well
Area of embankment × height of embankment= volume of earth dug out
Height of embankment= volume of earth dug out/area of the embankment
Height of the embankment = 2310 / 462
Height of embankment= 5 m
Hence, the height of the embankment so formed is 5 m ==================================================================
Hope this will help you.....
Given:
Inner Diameter of the well= 14 m
Inner Radius of the well (r) = 14/2 m = 7 m
Height of the well(h) = 15 m
Volume of the earth taken out of the well = πr²h
= 22/ 7 ×(7)²×15
= 22× 7×15= 2310 m³
Width= 7m
Outer radius of the embankment R =inner radius + width
Outer radius (R)= 7 + 7 = 14m
The embankment is in the form of cylindrical shell, so area of embankment
Area of embankment = outer area - inner area
= πR² - πr² = π(R²-r²)
= (22/7) ( 14² - 7²)
= 22/7(196-49)
= 22/7 × 147
= 22 × 21
= 462 m²
Volume of embankment= volume of earth taken out on digging the well
Area of embankment × height of embankment= volume of earth dug out
Height of embankment= volume of earth dug out/area of the embankment
Height of the embankment = 2310 / 462
Height of embankment= 5 m
Hence, the height of the embankment so formed is 5 m ==================================================================
Hope this will help you.....
Answered by
122
Solution :-
Both well and the embankment are in the shape of cylinder.
Since the mud is evenly spread all around the well to form the embankment, then the volume of well = volume of embankment
Volume of well = πr²h
Diameter = 14 m
then radius = 14/2 = 7 m
Height = 15 m
⇒ π*7*7*15
⇒ Volume of well = 735 π m³
Volume of the embankment -
The embankment is in the shape of a hollow cylinder.
It inner diameter = 14 m
So, Radius r = 14/2 = 7 m
Its outer radius R = inner radius + width
⇒ 7 + 7 = 14 m
Volume of inner part of the cylinder = πr²h
⇒ π(7)²*h
= 49 πh m³
Volume of the outer part of the cylinder = πR²h
⇒ π(14)²*h
⇒ 196 πh m³
Volume of embankment = Volume of outer part - Volume of inner part
⇒ 196 πh m³ - 49 πh m³
Volume of embankment = 147 πh m³
Now,
Volume of well = Volume of embankment
735 π m³ = 147 πh m³
⇒ h = 735/147
⇒ h = 5
So, the height of the embankment is 5 m
Answer.
Both well and the embankment are in the shape of cylinder.
Since the mud is evenly spread all around the well to form the embankment, then the volume of well = volume of embankment
Volume of well = πr²h
Diameter = 14 m
then radius = 14/2 = 7 m
Height = 15 m
⇒ π*7*7*15
⇒ Volume of well = 735 π m³
Volume of the embankment -
The embankment is in the shape of a hollow cylinder.
It inner diameter = 14 m
So, Radius r = 14/2 = 7 m
Its outer radius R = inner radius + width
⇒ 7 + 7 = 14 m
Volume of inner part of the cylinder = πr²h
⇒ π(7)²*h
= 49 πh m³
Volume of the outer part of the cylinder = πR²h
⇒ π(14)²*h
⇒ 196 πh m³
Volume of embankment = Volume of outer part - Volume of inner part
⇒ 196 πh m³ - 49 πh m³
Volume of embankment = 147 πh m³
Now,
Volume of well = Volume of embankment
735 π m³ = 147 πh m³
⇒ h = 735/147
⇒ h = 5
So, the height of the embankment is 5 m
Answer.
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