A well whose diameter is 3m, has been dug 21m deep and the earth dug out is used to form an embankment 4m wide around it. Find the height of the embankment.
Answers
Answered by
45
Hello Mate!
Volume of cylindrical well = πr²h
= 22/7 × (3/2)² × 21 m³
= 22/7 × 3/2 × 3/2 × 21 m³
= 148.5 m³
Now, same mud is spread in cylindrical shape around the well 4 m wide.
So area of embankment = π( R² - r² )
= π( R + r )( R - r )
= π ( 5.5 - 1.5 )( 5.5 + 1.5 ) m²
= 22/7 × 4 × 7 m²
= 88 m²
88 m² × h = 148.5 m³
Height = 1.6875 m or 1.7 m
Have great future ahead!
Volume of cylindrical well = πr²h
= 22/7 × (3/2)² × 21 m³
= 22/7 × 3/2 × 3/2 × 21 m³
= 148.5 m³
Now, same mud is spread in cylindrical shape around the well 4 m wide.
So area of embankment = π( R² - r² )
= π( R + r )( R - r )
= π ( 5.5 - 1.5 )( 5.5 + 1.5 ) m²
= 22/7 × 4 × 7 m²
= 88 m²
88 m² × h = 148.5 m³
Height = 1.6875 m or 1.7 m
Have great future ahead!
Attachments:
Answered by
1
Answer:
0.5235 m
Step-by-step explanation:
Since , Embankment is in the shape of cylinder . Since the earth is taken out from the well is used to make embankment . So, volume will be equal.
Similar questions