Question

A well with 10 m inside diameter is dug 14 m deep. Earth taken out of it is apread all a round toa width of 5 m to form an embankment. find​

Answer 1

Diameter of well = 10 m

Radius of well = $\frac{Diameter}{2} = \frac{10}{2} = 5m$

Depth of well = 14 m

Volume of well =$\pi r^{2} h$

                         =$\frac{22}{7} * 5^{2} *14$

                        = $1100m^{3}$

Earth taken out of it is spread all a round to a width of 5m to form an embankment.

Radius of embankment. = 5 m + 5 m = 10 m

Let the height of embankment be h

Volume of embankment = $\pi r^{2} h$

                                        = $\frac{22}{7} *10*h$

Since Earth taken out of it is spread all a round to a width of 5m to form an embankment. So, volume of well = Volume of embankment

So, $1100= \frac{22}{7} * 10^{2} *h$

     $1100*\frac{7}{22} * \frac{1}{10^{2} } \\\\= 3.5 = h$

Hence the height of the embarkment is 3.5 m.

Answer 2

Answer:

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