A well with 10 m inside diameter is dug 8.4 m deep. Earth taken out of it is spread all around it
to a width of 7.5 m to form an embankment. Find the height of the embankment
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Step-by-step explanation:
Heya
Here u go
.Radius of well,r=5m
and,it's depth=8.4m
so, volume of earth dug out=pi×r^2×h
=22/7×5×5×8.4
=550/7×8.4
=660m^3.
Width of embankment=7m
external radius =7+5=12m
internal radius =5m.
Area of embankment =
pi×[(12^2)-5^2]m^2
=22/7×(144-25)m^2
=(22/7×119)m^2
=374m^2.
therefore height =(660/374)m
=1.76471 m. now,
volume of embankment =pi×h×(R^2-r^2)
=22/7×1.76471×(12^2-5^2)
=5.54623×(144-25)
=5.54623×119
=660.00137 m^3
now, since the contractor has taken height as 2m therefore volume=pi×h×(R^2-r^2)
=22/7×2×(12^2-5^2)
=44/7×119
=44×17=748 m^3.
Now, cost per m^3=500
therefore cost of 660.00137 m^3=
660.00137×500=330000.685
Also, cost of 748 m^3=748×500=374000.
Therefore extra money made by him=374000-330000.685=Rs 43999.315
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