Question

(a) What activity is diagrammatically represented above?

(b)Name the devices labeled A and B

(c) What does W1 – W2 stand for?

(d)Define the principle involved in the activity named in (a).​

Answer 1

Answer:

a) to find the volume of an irregular solid

please follow

Answer 2

Answer:

Correct option is

A

5,

3

2

Upthrust acting on the block in water =15N−12N=3N = ( volume of solid immersed )( density of liquid ) g = V (1) 10 where V is the volume of the block , so V=

10

3

=0.3 cm

3

Block weighs 15N in air implies 15=mg , implies m=

10

15

=1.5g

now density =

volume

mass

=

0.3

1.5

= 5 g/cm

3

so density of block = 5 g/cm

3

hence , relative density of the block = density of block / density of water=

1

5

=5

now Upthrust acting on the block in the liquid =15N−13N=2N= (volume of solid immersed ) ( density of liquid ) g=Vρg=0.3( ρ)g ,

implies ρ of the liquid =

3

2

g/cm

3

so relative density of the liquid = density of liquid / density of water =

1

3

2

=

3

2

so option (A) is correct