Physics, asked by ayanalikhan97, 1 year ago

(a) What are the least count of these meters?
(b) What is the resistance of the resistor?​

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Answers

Answered by bodhigaikwad
4
2.450 is least count
and 1 ohm is ghe answer
Answered by 26Apoorv
20

a) Least count = Value/no. of divisions

So for mA meter, Least count

= 100/10 mA

= 10mA

And dor V meter, Least count

= 1/10 V

= 0.1 V

b) Current (I) = 250 mA = 0.250 A

EMF (V) = 2.4V

So R = V/I = 2.4/0.25 = 240/25 =9.6 Ohm

Hope it helps

Pls mark as brainliest


ayanalikhan97: how can there be 10divisions in miliammeter and votmeter as in the figures it is visible 5 divisions only
26Apoorv: In mA meter, no. of divisions, if you count, between 100mA and 200mA is 10 and in the voltmeter, it is like th Ammeter.
26Apoorv: So the divisons are 10
ayanalikhan97: thanks
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