Question

a. What is the force acting on the bottom of a swimming pool 8.0 m by 15.0 m whose uniform depth is 2.0 m?​
b. What is the absolute pressure at the bottom of the swimming pool 8.0 m by 15.0 m whose uniform depth is 2.0

Answer 1

Answer:

Pressure is defined as force per unit area, where the force F is understood to be acting perpendicular to the surface area, A.

Pressure=P=FA

The SI unit for pressure is N/m2. This unit is also known as a pascal (Pa): 1 Pa = 1 N/m2.

Answer 2

Answer:

The force acting on the bottom is 1,45,11,000 N, and the absolute pressure at the bottom of the pool is 120925 Pa

Explanation:

The pressure at the top of the pool is that of 1 atm, i.e.,

$P_{atm}$ = 101325 Pa

Pressure at the ground point be $P_{g}$

The pressure at any point is given by, Pressure = Height* Density * Acceleration due to gravity.

The absolute pressure will be the sum of the atmospheric pressure and the pressure at that point.

Hence, the absolute pressure at the bottom of the pool is:

$P_{t}$ = $P_{atm}$ + $P_{g}$  = 101325 atm + (2.0 m)(1000 kg/m3)(9.8 m/s2) = 120925 Pa

Area = Length * Breadth = 8 * 15 = 120 $m^{2}$

Now, We have,

Pressure = Force/ Area

So, Force = Pressure * Area = 120925 Pa * 120 $m^{2}$ = 1,45,11,000 N

Thus, The force acting on the bottom is 1,45,11,000 N, and the absolute pressure at the bottom of the pool is 120925 Pa

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