(a).What is the maximum potential energy gained by a ball of mass 0.20 kg
When it is thrown vertically upwards with an initial velocity of 20 m/s. [2]
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Answer:
40 kg/met.
Explanation:
potential energy =mgh
so we need to find h=?
u=20m/s
m=0.20kg
we have an equation
v^2=u^2-2gh
0=[20]^2-2×10×h
20h=400
h=20
then put the value of h in mgh.
mgh=0.20×10×20
mgh=40
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