Question

a) What is the nature of motion exhibited by the body in the sections OA, AB and BC?
b) What does the slope of this graph represent?
c) Find the velocity of the body in the time interval 2 - 3 seconds and 4 - 6 seconds.

Answer 1

Answer:

OA represents uniform acceleration since the slope of OA in the velocity-time graph is having a uniform positive slope. AB represents the uniform velocity of 20ms

−1

. Since the slope of AB is zero. hence, acceleration is zero.

(2) After 10 s, the velocity is 20ms

−1

up to 30 s and after 30 s, the velocity is uniformly restarted to zero after 40 s.

(3) Retardation is uniform and it is equal to the slope of BC, i.e.

Slope of BC =

DC

BD

=

40−30

20

=2ms

−2

And acceleration =−2ms

−2

(4) Distance covered by the body between the 10th and 30th second

=20×20=400metres