Question

a. What is the pressure exerted by a box of 20 N with an area of cross-section 5 m2?​

Answer 1

Answer:

4 Nm

Step-by-step explanation:

Pressure=$\frac{N}{m^{2} }$

Nm=$\frac{20N}{5m^{2} }$=4 Nm

Answer 2

Solution :-

Given ,

• Force applied on the box = 20N
• Area of cross - section = 5 m²

We need to find ,

• Pressure exerted by the box = ?

Finding pressure using ,

♦ P = F/A

Where ,

• P → Pressure = ?
• F → Force = 20N
• A → Area = 5 m²

Substituting the values we have ,

⇒ P = F/A

⇒ P = 20/5

⇒ Pressure exerted = 4 N/m²

Hence , pressure exerted by the box = 4 N/m²