Physics, asked by Anuragtalukdar, 10 months ago


a) What is the total distance
covered by the runner
in 16s
(m/s)?

b) What is the acceleration
of the runner at=11s​

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Answers

Answered by AtTiTuDeQuEeN15
8

Explanation:

a) The total distance is 130 m and the acceleration is zero at 11 second.

Explanation:

According to graph,

(a). The total distance covered in 16 seconds.

The total distance = Area of triangle +area of rectangular

(b). The acceleration of the runner at t = 11 seconds.

The velocity is not changing at 11 second so the acceleration will be zero.

Hence, The total distance is 130 m and the acceleration is zero at 11 second

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Answered by ratanvoleti
2

Answer:

Explanation:

The total distance is 130 m and the acceleration is zero at 11 second.

Explanation:

According to graph,

(a). The total distance covered in 16 seconds.

The total distance = Area of triangle +area of rectangular

(b). The acceleration of the runner at t = 11 seconds.

The velocity is not changing at 11 second so the acceleration will be zero.

Hence, The total distance is 130 m and the acceleration is zero at 11 second.

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