Question

A) what pressure is required to achieve a co2 concentration of 6.10102 m at 20c?

Answer 1

Explanation:

the air and can is very Lighter

Answer 2

Pressure (P) = 146.58 Latm

Explanation:

Relation between Pressure, temperature, volume and amount of gas can be combined in the Ideal gas law by the formula

                                              $PV=nRT$

This equation is called Ideal gas equation.

P, V, T, n are the Pressure, Volume, Temperature and amount of gas respectively.

R = Universal gas constant

                                               $P=(\frac{n}{V})RT$

 As we know ,                         $C=\frac{n}{V}$  

where C = Concentration  

                                               $P=CRT$                ......(i)

Given that           C = 6.10102 m

                            T = $20^{0}C = 20+273 K = 293 K$

                            $R = 0.082 (\frac{Latm}{molK})$

Put the above values in equation (i)

                      $P=6.10102mol\times 0.082\frac{Latm}{molK}\times293K$

                     $P = 146.58 Latm$

Therefore, for 6.10102 m concentration of $CO_{2}$ at $20^{0}C$, 146.58 Latm pressure is required.