Math, asked by dalladalla, 7 hours ago

a. What will be the output of the following: Math. Remainder(10,3) Math.SquareRoot(91) Math.Power(4,3)​

Answers

Answered by juhipandey539
0

Answer:

The value of iota, denoted as

i

, is √-1. This imaginary unit number is used to express complex numbers, where

i

is defined as imaginary or unit imaginary. Basically, the value of the imaginary unit number,

i

comes into the picture, when there is a negative number inside the square root, such that a unit imaginary number is equal to the root of -1. Therefore, the square of unit imaginary unit,

i

is equal to -1 and its cube is equal to the value -

i

. Similarly, we can evaluate other powers of iota by solving the expressions for different exponents. Higher powers of iota can be calculated by decomposing the higher exponents of

i

into smaller ones and thus evaluating the expression.

Answered by shreyasengupta1862
1

These outputs can be done v.i.a JAVA Programmes OR PYTHON Programmes

1) Math.Rem(10,3)

Output ( Remainder 10 on dividing a number by 3)

2) Math.sqrt(91)

Output ( \sqrt{91})

3) Math.pow(4,3)

Output ( 4^3)

Have a gr8 day!!!

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