Question

A wheat variety with coloured seeds is crossed to a colorless strain producing an all coloured F1. In the F2, 1/64 of the progeny has colourless seeds.How many pairs of genes control seed colour? What are the genotypes of parents and the F1 (use your own symbols)​

Answer 1

Answer:

ok

Explanation:

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Answer 2

3 pair of genes control seed color. genotype of the parents are AABBCC and aabbcc  and genotype of F1 is AaBbCc

Explanation:

• as colored phenotype is expressed in F1 so colored phenotype is dominant over colorless.
• so, colorless strains are always homozygous recessive and colored strains are either homozygous dominant or heterozygous.
• If we selfed F1 progeny, 1/64 of the progeny has colorless seed.

• Proportion of recessive homozygote in the F2 generation is 1/$(2^{n})^{2}$  
• $(2^{n} )^{2}$ = 64 , so n= 3 ,$(2^{3})^{2}$=$2^{6}$=64.
• So 3 pair of genes control seed color.
• in parental generation, colored parent have genotype AABBCC and colorless parental have genotype aabbcc. so if we cross colored parent with colorless parent, genotype of F1 plant will be AaBbCc.