A Wheatstone bridge consists of AB=4ohm,BC=3ohm,CD=6ohm and DA=5ohm. A 2 volt cell is connected between B and D and galvanometer of 10 ohms resistance between A and C. Find the current through the galvanometer.
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Answer:
R
net
=
40+120
(30+10)×(90+30)
+5
=35Ω
I=
R
net
V
=
35
7
=0.2A
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