Question

A Wheatstone network ABCD contains equal resistances P in the arms AB and CD and equal resistances Q in the arms AD and BC. A cell of emd 1v and negligible resistance is connected across AC . Calculate the pd between B and D​

Answer 1

Answer:

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Answer 2

Given,

• A Wheatstone network ABCD

• Equal resistances P in the arms AB and CD

• Equal resistances Q in the arms AD and BC

To find,

The potential difference between B and D.

Solution,

In the given Wheatstone bridge,

               B

    ---A             C---

               D

Current enters from A and exits the bridge from C.

To stop the current flow completely, the Wheatstone bridge should be balanced.

The condition is that the product of resistance in the wires AB and CD should be equal to the product of resistance between wires BC ad DA.

From the given data,

• Resistance in AB wire = P
• Resistance in BC wire = Q
• Resistance in CD wire = P
• Resistance in DA wire = Q

Product of resistance in the wires AB and CD = PQ

Product of resistance in the wires BC and DA = PQ

As the product satisfies the given condition, the Wheatstone bridge is balanced. No current flows through it.

The potential will be the same at all points.

Therefore, the potential difference between B and D will be zero.