Question

A Wheatstone’s bridge has resistance 10Ω, 10Ω, 10Ω & 30Ω in its four arms. What resistance joined in parallel to 30 Ω will bring it to balanced condition?

Answer 1

Answer:

15ohm

Explanation:

let

1. P=10ohm
2. Q=10ohm
3. R=10ohm
4. S=30ohm

We know in balanced condition

P/Q=R/S

Here P/Q=1

and R/S=1/3

The resistance which connected parallel to 30ohm resistance,

Resultant resistance=10

Now 10=30x/30+x

=>x=15ohm