A wheel at rest is rotated with a uniform angular acceleration, such that a particle on the rim of the wheel experiences a tangential acceleration of 20t ms-2. The radius of the wheel is 2 m. The instantaneous period of rotation at the end of 4 second
is
•0.08 second
•0.01 second
•0.02 second
•0.05 second
Answers
Answer:
Principal=20000
Rate =15
Time=3 years
C. I= P [{1+R/100}^n-1]
C. I = P [{ 1+15/100 }³-1]
C. I= P [ { 115/100}³ -1]
C. I= P [ {23/20}³-1]
C. I= P[(539/400)-1]
C. I =P[(529-400)/400]
C. I = P[129/400]
C. I= 20000(129/400)
C.I = 50×129
C.I= 6450
COMPOUND INTEREST =RS 6450Principal=20000
Rate =15
Time=3 years
C. I= P [{1+R/100}^n-1]
C. I = P [{ 1+15/100 }³-1]
C. I= P [ { 115/100}³ -1]
C. I= P [ {23/20}³-1]
C. I= P[(539/400)-1]
C. I =P[(529-400)/400]
C. I = P[129/400]
C. I= 20000(129/400)
C.I = 50×129
C.I= 6450
COMPOUND INTEREST =RS 6450Principal=20000
Rate =15
Time=3 years
C. I= P [{1+R/100}^n-1]
C. I = P [{ 1+15/100 }³-1]
C. I= P [ { 115/100}³ -1]
C. I= P [ {23/20}³-1]
C. I= P[(539/400)-1]
C. I =P[(529-400)/400]
C. I = P[129/400]
C. I= 20000(129/400)
C.I = 50×129
C.I= 6450
COMPOUND INTEREST =RS 6450Principal=20000
Rate =15
Time=3 years
C. I= P [{1+R/100}^n-1]
C. I = P [{ 1+15/100 }³-1]
C. I= P [ { 115/100}³ -1]
C. I= P [ {23/20}³-1]
C. I= P[(539/400)-1]
C. I =P[(529-400)/400]
C. I = P[129/400]
C. I= 20000(129/400)
C.I = 50×129
C.I= 6450
COMPOUND INTEREST =RS 6450Principal=20000
Rate =15
Time=3 years
C. I= P [{1+R/100}^n-1]
C. I = P [{ 1+15/100 }³-1]
C. I= P [ { 115/100}³ -1]
C. I= P [ {23/20}³-1]
C. I= P[(539/400)-1]
C. I =P[(529-400)/400]
C. I = P[129/400]
C. I= 20000(129/400)
C.I = 50×129
C.I= 6450
COMPOUND INTEREST =RS 6450Principal=20000
Rate =15
Time=3 years
C. I= P [{1+R/100}^n-1]
C. I = P [{ 1+15/100 }³-1]
C. I= P [ { 115/100}³ -1]
C. I= P [ {23/20}³-1]
C. I= P[(539/400)-1]
C. I =P[(529-400)/400]
C. I = P[129/400]
C. I= 20000(129/400)
C.I = 50×129
C.I= 6450
COMPOUND INTEREST =RS 6450Principal=20000
Rate =15
Time=3 years
C. I= P [{1+R/100}^n-1]
C. I = P [{ 1+15/100 }³-1]
C. I= P [ { 115/100}³ -1]
C. I= P [ {23/20}³-1]
C. I= P[(539/400)-1]
C. I =P[(529-400)/400]
C. I = P[129/400]
C. I= 20000(129/400)
C.I = 50×129
C.I= 6450
COMPOUND INTEREST =RS 6450Principal=20000
Rate =15
Time=3 years
C. I= P [{1+R/100}^n-1]
C. I = P [{ 1+15/100 }³-1]
C. I= P [ { 115/100}³ -1]
C. I= P [ {23/20}³-1]
C. I= P[(539/400)-1]
C. I =P[(529-400)/400]
C. I = P[129/400]
C. I= 20000(129/400)
C.I = 50×129
C.I= 6450
COMPOUND INTEREST =RS 6450Principal=20000
Rate =15
Time=3 years
C. I= P [{1+R/100}^n-1]
C. I = P [{ 1+15/100 }³-1]
C. I= P [ { 115/100}³ -1]
C. I= P [ {23/20}³-1]
C. I= P[(539/400)-1]
C. I =P[(529-400)/400]
C. I = P[129/400]
C. I= 20000(129/400)
C.I = 50×129
C.I= 6450
COMPOUND INTEREST =RS 6450Principal=20000
Rate =15
Time=3 years
C. I= P [{1+R/100}^n-1]
C. I = P [{ 1+15/100 }³-1]
C. I= P [ { 115/100}³ -1]
C. I= P [ {23/20}³-1]
C. I= P[(539/400)-1]
C. I =P[(529-400)/400]
C. I = P[129/400]
C. I= 20000(129/400)
C.I = 50×129
C.I= 6450
COMPOUND INTEREST =RS 6450Principal=20000
Rate =15
Time=3 years
C. I= P [{1+R/100}^n-1]
C. I = P [{ 1+15/100 }³-1]
C. I= P [ { 115/100}³ -1]
C. I= P [ {23/20}³-1]
C. I= P[(539/400)-1]
C. I =P[(529-400)/400]
C. I = P[129/400]
C. I= 20000(129/400)
C.I = 50×129
C.I= 6450
COMPOUND INTEREST =RS 6450Principal=20000
Rate =15
Time=3 years
C. I= P [{1+R/100}^n-1]
C. I = P [{ 1+15/100 }³-1]
C. I= P [ { 115/100}³ -1]
C. I= P [ {23/20}³-1]
C. I= P[(539/400)-1]
C. I =P[(529-400)/400]
C. I = P[129/400]
C. I= 20000(129/400)
C.I = 50×129
C.I= 6450
COMPOUND INTEREST =RS 6450Principal=20000
Rate =15
Time=3 years
C. I= P [{1+R/100}^n-1]
C. I = P [{ 1+15/100 }³-1]
C. I= P [ { 115/100}³ -1]
C. I= P [ {23/20}³-1]
C. I= P[(539/400)-1]
C. I =P[(529-400)/400]
C. I = P[129/400]
C. I= 20000(129/400)
C.I = 50×129
C.I= 6450
COMPOUND INTEREST =RS 6450Principal=20000
Rate =15
Time=3 years
C. I= P [{1+R/100}^n-1]
C. I = P [{ 1+15/100 }³-1]
C. I= P [ { 115/100}³ -1]
C. I= P [ {23/20}³-1]
C. I= P[(539/400)-1]
C. I =P[(529-400)/400]
C. I = P[129/400]
C. I= 20000(129/400)
C.I = 50×129
C.I= 6450
COMPOUND INTEREST =RS 6450Principal=20000
Rate =15
Time=3 years
C. I= P [{1+R/100}^n-1]
C. I = P [{ 1+15/100 }³-1]
C. I= P [ { 115/100}³ -1]
C. I= P [ {23/20}³-1]
C. I= P[(539/400)-1]
C. I =P[(529-400)/400]
C. I = P[129/400]
C. I= 20000(129/400)
C.I = 50×129
C.I= 6450
COMPOUND INTEREST =RS 6450Principal=20000
Rate =15
Time=3 years
C. I= P [{1+R/100}^n-1]
C. I = P [{ 1+15/100 }³-1]
C. I= P [ { 115/100}³ -1]
C. I= P [ {23/20}³-1]
C. I= P[(539/400)-1]
C. I =P[(529-400)/400]
C. I = P[129/400]
C. I= 20000(129/400)
C.I = 50×129
C.I= 6450
COMPOUND INTEREST =RS 6450