A wheel at rest is rotated with a uniform angular acceleration, such that a particle on the rim of the wheel experiences a tangential acceleration of 20t ms-2. The radius of the wheel is 2 m. The instantaneous period of rotation at the end of 4 second
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Explanation:
Angle revolved in 1 sec and 2 sec are θ1 and θ1+θ2 respectively.
Given: w1=0 using θ=21αt2
θ1=21α(1)2
θ1+θ2=21α(2)2
Solving we get, θ2=23α
Thus θ1θ2=3
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