Question

A wheel has angular acceleration of 3.0 rad/sec^2 and an initial angular speed of 2.00 rad/sec.

Answer 1

The angular acceleration is α=3rads−2

The initial angular speed is ω0=2rads−1

The time is t=2s

Apply the equation

θ=ω0t+12αt2

The angle is

θ=2⋅2+12⋅3⋅22

=4+6

=10rad