Question

A wheel has angular acceleration of 5 rad/s2 when a torque of 1 N-m acts on it. Calculate its Moment of Inertia. ho​

Answer 1

Answer:

• 5Kgm² is the required moment of Inertia.

Explanation:

According to the Question

It is given that,

• Angular Acceleration , a = 5rad/s²
• Torque ,τ = 1

we have to calculate its moment of inertia .

As we know the relationship between angular acceleration , torque & moment of inertia.

Moment of Inertia (l) is calculated by

Moment of Inertia = Torque/AngularAcceleration

substituting the value we get

↠ Moment of Inertia = 5/1

↠ Moment of Inertia = 5 Kgm²

• Hence, the moment of Inertia is 5 Kgm².

Answer 2

Explanation:

Answer:

5Kgm² is the required moment of Inertia.

Explanation:

According to the Question

It is given that,

Angular Acceleration , a = 5rad/s²

Torque ,τ = 1

we have to calculate its moment of inertia .

As we know the relationship between angular acceleration , torque & moment of inertia.

Moment of Inertia (l) is calculated by

Moment of Inertia = Torque/AngularAcceleration

substituting the value we get

↠ Moment of Inertia = 5/1

↠ Moment of Inertia = 5 Kgm²

• Hence, the moment of Inertia is 5 Kgm².

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