Question

A wheel has MOI = 5¥10^-3 is making 20 rps it is stopped in 20 sec , the angular retardation is?​

Answer 1

Answer:

Explanation:

\huge\underline\orange{Answer}

\large{\boxed{{\tau = 6.28×{10}^{-2}N-m}}}

\huge\underline\orange{Solution}

Given :-

\large{I=5×{10}^{-3}}

No. of Rev/sec (v)= 20

Time (t) = 10 s

Angular Velocity :-

\large{{\omega = 2πv}}

\large{{\omega = 2π×20}}

\large{\boxed{{\omega = 40πrad/s}}}

Angular Acceleration :-

\large{\boxed{{\alpha={\frac{\omega}{t}}}}}

\large{{\alpha ={\frac{40π}{10}}}}

\large{\boxed{{\alpha = 4π rad/{s}^{2}}}}

Torque :-

\large{\boxed{{\tau = I{\alpha}}}}

\large{{\tau = 5×{10}^{-3}×4π}}

\large{{\tau = 62.3×{10}^{-3}}}

\large\blue{\boxed{{\tau=6.23×{10}^{-2}N-m}}}

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