Question

A wheel having a diameter of 3 m starts from rest and accelerates uniformly to an
angular velocity of 210 R.P.M in 5 seconds. Angular acceleration of the wheel is

Answer 1

Given :-

A wheel having a diameter of 3 m starts from rest and accelerates uniformly to an angular velocity of 210 R.P.M in 5 seconds. Angular acceleration of the wheel is ?

Solution :-

• First, let us convert R.P.M (rotations per minute) into rad/sec

  $\rightarrow$ 1 rpm = $\sf\frac{\pi}{30} rad/sec$

  $\rightarrow$ 210 rpm = 7π rad/sec

• We need to calculate angular acceleration

• We know that :-

$\rightarrow$ ω = ω₀ + αt

   Where :-

   → ω = final angular velocity = 7π rad/sec (We found out earlier)

   → ω₀ = initial angular velocity = 0 (Given)

   → α = angular acceleration

   → t = time taken = 5s (Given)

$\rightarrow$ 7π = 0 + α(5)

$\rightarrow$ α = $\sf\frac{7\pi}{5}$ = 1.4π rad/sec²

∴ The angular acceleration of the wheel is 1.4π rad/sec²

__________________________________

Thank you, pelase mark as brainliest!

$\rightarrow$ Sathvik :)

Answer 2

1.4 pi rad /s 2 is answer

Mark as brainlist pls