Question

A wheel having a rotational inertia of 0.20 kg-m2

rotates at 360 rpm about a vertical axis. What is the angular

speed of the wheel when a torque of 1 Nm is applied about the same axis for 3.0 sec​

Answer 1

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ANSWER

Given, l=2kg−m

2

,ω

0

=

60

60

×2πrad/s

ω

0

and t=60s

The torque required to stop the wheel's rotation is

τ=lα=l(

t

ω

0

−ω

)

τ=

60×60

2×2π×60

=

15

π

N−m