Question

A wheel having moment of inertia 4kg m2 its central axis rotates at rate of 240rpm about it

Answer 1

$\huge\underline\orange{\mathcal Answer}$

$\large\blue{\boxed{\mathcal Torque = {\frac{8\pi}{15}}}}$

$\huge\underline\orange{\mathcal Solution :-}$

Given :-

Moment of inertia = 4kg/m2

$\large{\omega = 240 rpm}$

Change it into rad/s

$\large{240 \times 2\pi \times {\frac{1}{60}}}$

$\large{\omega = 8\pi rad/s}$

$\large{\alpha ={\frac {\omega}{t}}}$

Time (t) is given 1 min change it into second i.e. 60 seconds

$\large{\alpha = {\frac{ 8π}{60}}m/{s}^{2}}$

$\large{Torque = I{\alpha}}$

$\large{Torque = 4 {\times{\frac{ 8\pi}{60}}}}$

$\huge{\boxed{Torque = {\frac{8\pi}{15}}}}$

Answer 2

$\huge{\boxed{{\frac{8π}{15}}}}$

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