Question

a wheel mass 10 kg has a moment of inertia of 160mm about its own axis the radius ​

Answer 1

I=mr2

I=10kg×160 ×160×10 ki power -6= 256×10 ki power -3 kg ×m2

Answer 2

Given moment of inertia of the wheel about its axis is 160kgm^2

I=MK^2 (K is the radius of gyration)

160=10×K^2

K=4m

Radius of gyration of the wheel about its own axis is 4 m.