A wheel of diameter 20 cm is rotating at 600 rpm. The linear velocity of the particle at its rim is *
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Answers
Answered by
34
Radius = 10 cm = 0.1 metre
Angular velocity = 600 revolution per minute
= 600*2π/60 radian/second
= 20π rad / sec
Linear velocity of the point at rim = Radius*Angular velocity = 0.1*20π = 2π metres/second = 6.28 m/s
Angular velocity = 600 revolution per minute
= 600*2π/60 radian/second
= 20π rad / sec
Linear velocity of the point at rim = Radius*Angular velocity = 0.1*20π = 2π metres/second = 6.28 m/s
Answered by
10
Answer: 6.28 m/s
Explanation:
The angular speed of the wheel = 600 rpm
α = 600 × 2π/60 = 62.8 rad/s
The diameter of wheel, d = 20 cm = 0.20 m
Radius of wheel, r = d/2 = 0.10 m
The relation between liner velocity and angular velocity is:
v = αr = 62.8 rad/s × 0.10 m = 6.28 m/s
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