Physics, asked by balinenisagarnaidu, 1 year ago

A wheel of diameter 20 cm is rotating at 600 rpm. The linear velocity of the particle at its rim is *
1 point

Answers

Answered by dhruvsh
34
Radius = 10 cm = 0.1 metre

Angular velocity = 600 revolution per minute
= 600*2π/60 radian/second
= 20π rad / sec

Linear velocity of the point at rim = Radius*Angular velocity = 0.1*20π = 2π metres/second = 6.28 m/s
Answered by ariston
10

Answer: 6.28 m/s

Explanation:

The angular speed of the wheel = 600 rpm

α = 600 × 2π/60 = 62.8 rad/s

The diameter of wheel, d = 20 cm = 0.20 m

Radius of wheel, r = d/2 = 0.10 m

The relation between liner velocity and angular velocity is:

v = αr = 62.8 rad/s × 0.10 m = 6.28 m/s

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