Question

A wheel of diameter 2m can be rotated about an axis passing through its centre by a moment of force equal to 2.0 N m. what minimum force must be applied on its rim?​

Answer 1

Step-by-step explanation:

Ans.

$\text{\( \because \) Diameter \( \rm =2 m \)}$

radius OP=1 m

$\text{\( \therefore \: \: \: \: \perp \) distance \( \rm O P=1 m \)}$

Moment of force =2.0 N m

$\text{\( \rm F \times \perp \) distance \( \rm O P= \) moment of force}$

$\rm F \times 1=2.0$

$\\ \rm F=\frac{2}{1} \boxed{\red{ \rm =2 N }}$