Math, asked by seohyng, 1 day ago

A wheel of diameter 2m can be rotated about an axis passing through its centre by a moment of force equal to 2.0 N m. what minimum force must be applied on its rim?​

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Answered by eashu53
6

Solution:

Diameter = 2m

Radius = 1m

Therefore, \bot distance = 1m

Moment of force = 2.0 Nm

Moment of force = Force \times\bot distance

2.0 Nm = 25 \times \bot distance

2.0 Nm = F \times 1 m

F = 2

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