A wheel of diameter 2m can be rotated about an axis passing through its centre by a moment of force equal to 2.0 N m. what minimum force must be applied on its rim?
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Solution:
Diameter = 2m
Radius = 1m
Therefore, \bot distance = 1m
Moment of force = 2.0 Nm
Moment of force = Force \times\bot distance
2.0 Nm = 25 \times \bot distance
2.0 Nm = F \times 1 m
F = 2
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