A wheel of diameter 2m can be rotated about an axis passing through its centre by a moment of force equal to 2.0 N m. what minimum force must be applied on its rim?
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3
Answer:
Diameter (perpendicular distance) =2m
Moment if force =2Nm
Force =?
moment of force =diameter * force
Force = moment of force/diameter
Force=2Nm/2m
=1N
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1
Answer:
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Step-by-step explanation:
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