Question

A
wheel of diameter 8 m can be rotated about an axis passing
through its centre by a moment
of force equal to 16.0 N m.
What minimum force must be applied on its rim?

Answer 1

Answer:

• 4 N.

Explanation:

Given: Perpendicular distance (d) = 8m [Diameter]

• Radius = 8/2 = 4m

& Moment of force = 16 Nm

To find: Force applied (F)

Solution: Moment of force = F × d

=> 16 = F × 4

=> 16 = 4F

=> F = 16/4 = 4 N

∴ The minimum force that must be applied on its rim is 4 N.

Verification: F × d

=> 16 = 4 × 4

=> 16 = 16 ∴ L.H.S = R.H.S

Answer 2

Answer:

4n

Explanation:

m = f * p