Question

A wheel of mass 4 kg and radius of gyration 0.4 m is making 300 r.p.m. Its moment of inertia is_______.​

Answer 1

Inertia = L/w = 300*4*0.4/10 = 48

Answer 2

Answer:

The moment of inertia of the wheel is 0.64kg-m².

Explanation:

The moment of inertia is given as,

$I=MK^2$      (1)

Where,

I=moment of inertia

M=mass of the body

K=radius of gyration

From the question we have,

The mass of the wheel(M)=4kg

The radius of gyration(K)=0.4m

By substituting the value of "M" and "K" in equation (1) we get;

$I=4\times (0.4)^2$

$I=0.64kg-m^2$

Hence, the moment of inertia of the wheel is 0.64kg-m².